Question

I will give 25 points and brainy from right answers (Please answer all!)!!!

(Use the first picture) 1. Which pair of angles is a liner pair?

A. "Angle" KRE and "Angle" ERT

B. "Angle" ERT and "Angle" MRC

C. "Angle" MRC and "Angle" KRM

D. "Angle" KRC and "Angle" CRH

(Use second Image) 2. The lines intersect at point H

Find m"Angle"BHR

A. 40°

B. 50°

C. 85°

D. 90°

(Use third image) 3. The lines intersect at point M.

What is the value of X?

A. 20

B. 35

C. 105

D. 128

4. An angle measures at 41°. What is the measure of its complement ?

A. 39°

B. 49°

C. 129°

D. 139°

(PLEASE ANSWER ALL!!!))

Answer 1

1. D. because the angels of KRC and CRH added together is 180 degrees. Which equals a straight line.

2. Answer is A . BHR is equal to NHD, so it is 8x. But we need to find x first.
The right angle in the picture is 8x + (9x +5)
90 =8x + 9x +5
90 = 17x + 5
85 = 17 x
5 = x.
X is 5 so 8x is 40.

3. B. The opposite angles are equal to each other. and the sum of two angles side by side equal 180.
6x - 82 = 3x +23
group like terms
6x - 3x = 23 + 82
3x = 105
x = 35.
Answer is B
4.B. a complement angle added together will get you 90.
90 - 41 = 49
Answer is B

Answer 2

1.D

2.A

3.B

4.
`49^(\circ)`

Explanation:

1.We have to find he pair of linear angles

From given figure

`\angle KRM+\angle MRH=180^(\circ)`

`\angle KRT+\angle KRM=180^(\circ)`

`\angle MRH+\angle HRT=180^(\circ)`

`\angle KRT+\angle HRT=180^(\circ)`

`\angle ERM+\angle MRC=180^(\circ)`

`\angle ERT+\angle CRT=180^(\circ)`

`\angle ERT+\angle ERM=180^(\circ)`

`\angle CRH+\angle HRE=180^(\circ)`

`\angle KRC+\angle CRH=180^(\circ)`

Hence, option D is true.

2.We have to find the angle BHR

`\angle NHD+\angle SHD=90^(\circ)`

`8x+9x+5=90`

`17x=90-5`

`17x=85`

`x=(85)/(17)`

`x=5`

substitute the value of x

Then
`\angle SHD=9*5+5=50^(\circ)`

`\angle SHD+\angle RHS+\angle BHR=180^(\circ)`

`90+50m\angle BHR=180`

`\angle BHR=180-140=40^(\circ)`

Hence,
`m\angle BRH=40^(\circ)`

Option A is true.

3.We have to find the value of x

`6x-82=3x+23` (vertical angles are equal )

`6x-3x=23+82`

`3x=105`

`x=(105)/(3)=35`

Hence, the value of x=35

Option B

4.We are given that an angle measure
`41^(\circ)`

We have to find the value of its complement

We know that complete angles sum is equal to 90 degrees

Therefore, complement =90-41=[/tex]49^{\circ}[/tex]

Hence, the complement of 41 degrees is 49 degrees.

Option B