Assuming angle a and angle b are not equal and the given triangle is a right triangle .
Let's see cos(90-b)
Here we use the formula of cos(A-B)=cos A cos B -sin A sin B
And on using this formula,we will get
cos(90-b)= cos 90 cos b + sin 90 sin b
Value of cos 90 = 0 and sin 90 =1 , And on using these values, we will get
cos(90-b) = (0) cos (b) + (1) sin (b)
cos(90-b) = 0 + sin (b)
cos(90-b) =sin(b)
As we see that on using the formula, we are getting cos(90-b)= sin b .
So the correct option is cos(90-b)= sin b