Question

2. The side of a square exceeds the side of

another square by 5 cm. The difference of
their areas is 325 sq. cm. Find the sides of
each square.​

Answer 1

`x=30cm`

`y=30+5=>35cm`

Explanation:

From the question we are told that

Sides difference
`\triangle x= 5cm`

Area difference
`\triangle a=326sq.cm`

Let first square be A

Let second square be B

Generally the area of a square is mathematically given by

Area of a square
`A=x*x=x^2`

Area of a square
`B=(x+5)^2=x^2+25+10x`

`Area \A - Area\ B =325`

Therefore from the equations above

`x^2+25x+10-x^2=325`

`10x=325-25`

`x=300/10`

`x=30cm`

Therefore

Side of the first square

`x=30cm`

Side of the second square.

`y=>30+5=35cm`

Check answer

`35^2-30^2=325`