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For the following system, use the second equation to make a substitution for y in the first equation.

2x + y = 5
y + 3 = 2x

A) 2x + 2x - 3 = 5
B) 2x + 3 - 2x = 5
C) 2x + 2x + 3 = 5

User Raxr
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A) 2x + 2x - 3 = 5

Turn the second equation into the y = mx + b format to where it's y = 2x - 3. Then plug into the first equation for y.
User Skatun
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