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What is the equation, in slope-intercept form, of the line that is perpendicular to the line y – 4 = –(x – 6) and passes through the point (−2, −2)? y = –x – y = –x + y = x – 1 y = x + 1
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Jul 5, 2019
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What is the equation, in slope-intercept form, of the line that is perpendicular to the line y – 4 = –(x – 6) and passes through the point (−2, −2)? y = –x – y = –x + y = x – 1 y = x + 1
Mathematics
college
Bayard Randel
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y – 4 = –(x – 6)
y - 4 = -x + 6
y = -x + 2 with slope = -1
perpendicular slope is opposite and reciprocal so slope = 1
passes through the point (−2, −2)
y + 2 = 1(x + 2)
y + 2 = x + 2
y = x
answer
y = x
LowFatTwinkie
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Jul 10, 2019
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LowFatTwinkie
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