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A particle moves along the x-axis with velocity v(t) = t2 - 1, with t measured in seconds and v(t) measured in feet per second. find the total distance travelled by the particle from t = 0 to t = 2 seconds. 0.667 4 none of these 2

User Black Flag
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2 Answers

13 votes

Answer:

help me plzz

Explanation:

The velocity of a particle moving along the x-axis is v(t) = cos(2t), with t measured in minutes and v(t) measured in feet per minute. To the nearest foot find the total distance travelled by the particle from t = 0 to t = π minutes

User Poetryrocksalot
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2 votes

Answer:

0.667 feet

Explanation:

To get the total distance travelled, we would integrate the velocity v(t) equation with respect to time t.

Given that the particle moves from t = 0 to t = 2 seconds

Integrating v(t) = t2 - 1

we get

= t^3/3 - t

substituting the boundaries from t = 0 to t = 2 seconds, we get

= 2^3/3 - 2 - (0^3/3 - 0)

= 8/3 - 2 - 0

= 0.667 feet

User Sarreph
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