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I will give 20 points for correct answer!

(Use first Image) 1. Which is the correct name for this angle?

A. "Angle" DGH

B. "Angle" DEG

C. "Angle" DEH

D. "Angle" GHF

(Use second image) 2. Which statement is true CH = 6?

( Line over a letters. Equals signs with a ~ over it )

A. MN = ST

B. HT = HN

C. MH = HN

D. ST = MH

(Use third image) 3. ( Line over a letters DF & EG.) Which is the intersection of DF and EG?

( Line over a letters DE, FG & EF))

A. point F

B. DE

C. FG

D. EF

(Use the forth image) 4. (Arrow going right on letters BD & CB ) What is the intercetion between BD & CB?

(Arrow going right on letters BD) (Line on letters BC)

A. line B

B. line t

C. BD

D. BC

I will give 20 points for correct answer! (Use first Image) 1. Which is the correct-example-1
I will give 20 points for correct answer! (Use first Image) 1. Which is the correct-example-1
I will give 20 points for correct answer! (Use first Image) 1. Which is the correct-example-2
I will give 20 points for correct answer! (Use first Image) 1. Which is the correct-example-3
I will give 20 points for correct answer! (Use first Image) 1. Which is the correct-example-4

2 Answers

4 votes
1. A. The middle letter has to be G b/c that is the vertex of the angle.
2. D. They both equal 10.
3. D. Hard to explain, but this is the section that overlaps.
4. D. Same as the previous one.
User Koalaok
by
5.5k points
5 votes

Answer:

1.A

2.D.

3.D

4.D

Explanation:

1.We are given that an angle

We have to find the name of given angle.

G is the vertices of given angle.

We know that vertices is always write in mid of the name of an angle

Suppose an angle ABC with vertices B.

There is B is in the middle of given name ABC.

Therefore, the correct name of given angle is Angle DGH.

Hence, option A is true.

2.We are given that CH=6

We have to find that statement for which is CH=6

We are given that SH=CM=4

HT=6

ST=4+6=10

CH=6

MH=MC+CH=4+6=10

Hence, MH=ST

Therefore, option D is true.

3.We are given that line DF and EG

We have to find the intersection of DF and EG

DF=DE+EF

EG=EF+FG

EF is common in both lines .Therefore, EF is the intersection of line DF and EG.

Hence, option D is true.

4.We are given that BD and CB

We have to find the intersection of BD and line BC

BD=BC+CD

BC is common in both therefore,BC is the intersection of both BD and line CB.

Hence, option D is true.

User Heiko Hatzfeld
by
5.4k points