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Calculate the mass of water produced when 7.66 g of butane reacts with excess oxygen

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2C4H10+13O2---›8CO2 +10H2O
n(C4H10)=m/M=7,66g/58g/mol=0,132mol
n(H2O)=5n(C4H10)=0,66mol
m(H2O)=n*M=0,66mol*18g/mol≈11,87g
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