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How many grams of oxygen are required to react with 12.0 grams of octane in the combustion of octane in gasoline?

How many grams of oxygen are required to react with 12.0 grams of octane in the combustion of octane in gasoline?
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How many grams of oxygen are required to react with 12.0 grams of octane in the combustion of octane in gasoline?

User Usama Ejaz
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2 C8H18(g) + 25 O2(g) → 16 CO2(g) + 18 H2O(g)

(10.0 g C8H18) / (114.2285 g C8H18/mol) x (25 mol O2 / 2 mol C8H18) x (31.99886 g O2/mol) = 35.0 g O2
please return the favor and answer question in my profile thanks
User Piotr Z
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