Question

Combine these radicals

-6 √100+ √36

A. -66
B. -54
C. -6 √136
D. -6 √16

Please help!!

Answer 1

-6√100+√36=-6(10)+6=-60+6=-54

Answer: B. -54

Answer 2

option B is correct

-54

Explanation:

Using radical and exponent laws:

`\sqrt[n]{a^n} = a`

Given that:

`-6√(100)+√(36)`

we can write 100 and 36 as:

`100 = 10 \cdot 10= 10^2`

`36 = 6^2`

then;

`-6√(10^2)+√(6^2)`

Apply the rule;

`-6\cdot 10+6`

`-60+6`

Combines constant terms;

`-54`

Therefore, Combine the given radicals we get, -54