Question

How much water should be mixed with 237 ml of​ ammonia, whose strength is​ 100%, in order to create a mixture that is diluted to a​ 75% strength.

Answer 1

Let the amount of water to be mixed = x ml
new mixture = 237+x
The new mixture is diluted to 75% strength i.e. 75/100
75/100 = 3/4
Therefore,
237/(237+x) = 3/4
4 *237 =3 (237+x)
948=711+3x
3x=948-711
3x=237
x=237/3
x=79
The amount of water to be mixed with ammonia = 79ml

Answer 2

Let the x ml of water be mixed with 237 ml of ammonia whose strength is 100%, in order to create a mixture of 75% strength.
The equation required to solve this will be:
237/(237+x)=75/100
solving for x we get:
237/(237+x)=3/4
237×4=3(237+x)
948=711+3x
3x+711=948
3x=948-711
3x=237
x=237/3
x=79 ml
therefore the amount of water to be added will be 79 ml