Question

Explain which method to use in 4x^2-27=0

Answer 1

Answer:

4x^2 = 27
x^2= 27/4
x= +/- sqrt(27/4)
x=+/- 3*sqrt(3)/(2)

Answer 2

so if we have 4x^2 - 27 = 0 then by using the square root properties we get:

4x^2 = 27
x^2= 27/4
x= +/- sqrt(27/4)
x=+/- 3*sqrt(3)/(2)

hope this helps! any questions please just ask! Thank you!!