a) If the current dimensions are 140 x 300 ft, and each dimension is to be increased by x ft, the new dimensions will become (140+x) x (300+x) ft. Therefore the new floor area will be A = (140+x)(300+x) or 42000 + 440x + x^2 ft.
b) Since we know that this new area is 1.5 times that of the old area:
42000 + 440x + x^2 = 1.5(140)(300)
42000 + 440x + x^2 = 63000
x^2 + 440x - 21000 = 0
x = 43.44 ft
Therefore, the new width is 140+x = 183.44 ft, and the new length is 300+x = 343.44 ft.
c1) If we increase the width by x, then we increase the length by twice this amount, or 2x. Our area will then be A = (140+x)(300+2x) = 42000 + 580x + 2x^2.
c2) If this is 1.5 times the original area:
42000 + 580x + 2x^2 = 1.5(140)(300)
42000 + 580x + 2x^2 = 63000
2x^2 + 580x - 21000 = 0
x = 32.55
So the width is 140+x = 172.55 ft, and the length is 300+2x = 365.10 ft.