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If we place 15 moles of NaN3, how many grams of NaN3 do you have before the reaction?
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12 votes
If we place 15 moles of NaN3, how many
grams of NaN3 do you have before the
reaction?

User Isengo
by
7.0k points

1 Answer

3 votes

Answer:

25.8 g C6H12O6

Step-by-step explanation:

User Xyv
by
6.8k points
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