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If a rock climber accidentally drops a 52.5-g piton from a height of 325 meters, what would its speed be just before striking the ground? ignore the effects of air resistance.
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If a rock climber accidentally drops a 52.5-g piton from a height of 325 meters, what would its speed be just before striking the ground? ignore the effects of air resistance.

User AkaDrHouse
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1 Answer

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Ignoring air resistance, the Kinetic energy before hitting the ground will be equal to the potential energy of the Piton at the top of the rock.
So we have 1/2 MV^2 = MGH
V^2 = 2GH
V = âš2GH
V = âš( 2 * 9.8 * 325)
V = âš 6370
V = 79.81 m/s
User Sedar
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