Question

Simplify quantity 4 x squared plus 12 x minus 16 all over quantity 2x plus 10 over quantity 6 x plus 24 over quantity x squared plus 9x plus 20

Answer 1

the answer is: (x-1)(x+4)/3
hope this helped! (:

Answer 2

`(4x^2+12x-16)/((2x+10)/((6x+24)/(x^2+9x+20)))`

Here we have two fractions top and bottom

`(4x^2+12x-16)/(2x+10)` divide by
`(6x+24)/(x^2+9x+20)`

We have division in between . we reverse the second fraction and multiply it with first fraction.

`(4x^2+12x-16)/(2x+10)` *
`(x^2+9x+20)/(6x+24)`

Now we factor both numerator and denominator

4x^2+12x-16 = 4 (x+4)(x-1)

2x+10 = 2(x+5)

x^2+9x+20 = (x+5)(x+4)

6x+24 = 6(x+4)

Replace the factors,

`(4 (x+4)(x-1))/(2(x+5))` *
`((x+5)(x+4))/(6(x+4))`

We cancel out same factors at the top and bottom

So it becomes ,
`((x-1)(x+4))/(3)`