Question

A tuning fork vibrating at a frequency of 512hz is held over the top of the jar filled with water and filled with a tap at the bottom. If the jar is 60cm tall and the speed of sound is 350ms-1, determine 1st and 2nd resonance.

Answer 1

Frequency of tuning fork f = 512 Hz
Speed of sound V = 350ms-1
Height of the jar = 60 cm = 0.06 m
Velocity = wavelength x frequency => V = lambda x f => lambda = V / f = 350 / 512
Wavelength = 350 / 512 = 0.684
1st resonance at = lambda / 4 = 0.684 / 4 = 0.171 = 17 cm
2nd resonance at = (3 x lambda)/ 4 = (3 x 0.684) / 4 = 0.513 = 51 cm