Question

A 1400 kg car has an engine that exerts 9800 N of force. If the force of friction between the car and the road is roughly 2801 N, what is the car's acceleration?

Answer 1

Friction opposes the force provided by the car's engine, so by Newton's second law the acceleration a is such that

∑ F = 9800 N - 2801 N = (1400 kg) a

a = (6999 N) / (1400 kg) ≈ 5.0 m/s²