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Prove that the product of the second and third numbers out of four consecutive whole numbers is two greater than the product of the first and the fourth numbers.

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Let the four consecutive numbers be x,x+1,x+2,x+3.

Now the product of second and third number=(x+1)(x+2)=x²+3x+2=k

Product of first and fourth number=x(x+3)=x²+3x=k-2

A.T.Q

product of second and third number= product of first and fourth number+2

Hence proved

User Yaroslav Draha
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