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One number is five more than twice another. If their sum is decreased by ten, the result is twenty-two. Find the numbers.
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5 votes
One number is five more than twice another. If their sum is decreased by ten, the result is twenty-two. Find the numbers.

User Alex Rashkov
by
5.9k points

2 Answers

4 votes
x = 2y + 5
(x + 2y + 5) - 10 = 22
(2y + 5 + 2y + 5) = 4y + 10
(4y + 10) - 10 = 22
4y = 22 y = 5.5
x = 2(5.5) + 5 x = 16
x = 16 y = 5.5

User Michaellindahl
by
6.1k points
4 votes
(x+2x+5)-10=22
3x+5=32
3x=27
x=9
So, the numbers are 3 and 11

User Cldwalker
by
6.0k points
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