Question

Find three consecutive odd integers such that the sum of three times the smaller and twice the largest is equal to one less than four times the middle. find the integers.

Answer 1

-1, 1, 3

Explanation:

Let x equal the first odd integer.

The three consecutive odd integers would be represented by x, then x+2, then x+4.

So 3x + 2(x + 4) = 4(x + 2) - 1

Solve for x

3x + 2x + 8 = 4x + 8 -1

5x + 8 = 4x + 7

x = -1