Question

An isosceles triangle has legs that are each `x` inches long and a base that is `y` inches long. The perimeter of this triangle is 38 inches. The base is 8 inches shorter than the length of a leg.

How long are the sides of the triangle?

Answer 1

15.333 inches

Explanation:

First find the value of “y" which is the base and it is 8 inches shorter than the length legs of the triangle.

y = x - 8

Then substitute the values in the formula for the perimeter of an isosceles triangle.

Perimeter = 2 (L) + b

38 = 2 (x) + x - 8

38 = 2x + x - 8

38 = 3x - 8

38 + 8 = 3x

3x = 46

x = 15.333 inches

x is the length of the triangle and it's actual value is 15.333 inches