Question

14 points, I need an answer ASAP!!

1) Part A-Find the PERIMETER of the outside edges of the frame. (Please explain and show work)
Part B-Find the AREA of the inside of the frame where the picture would belong and the area of the entire frame using the outside values. (Please explain and show work)
2) IF the area of the frame was 64 inches², what would be 2 possible sets of dimensions that could be used to make a frame with that area? (Please explain and show work)
4) The frame is being enlarged to hang on a gallery wall. Using the scale factor of 1in=2.5ft., give the new dimensions of the outside edges of the frame. (Please explain and show work)

Answer 1

Hey there,

Your question states: Part A-Find the PERIMETER of the outside edges of the frame.

You will do 5+5+7+7 and you will get 24.

Your correct answer would be 24 ft
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Your question states: Find the AREA of the inside of the frame where the picture would belong and the area of the entire frame using the outside values. So I will basically do everything I did for (Part A) but I will do 25 x 35 and this would give me 875.

The area of the frame above would be 875 ft.
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Your question states: If the area of the frame was 64 inches², what would be 2 possible sets of dimensions that could be used to make a frame with that area?

You would do 64/4 because this is a square and a square has 4 sides. So I will do 64/4 and I will get 16.

16 will be your correct answer.
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Your question states: The frame is being enlarged to hang on a gallery wall. Using the scale factor of 1in=2.5ft., give the new dimensions of the outside edges of the frame.

So if each each equals 2.5. I will do 2.5 x 5 and that will give me 12.5. I will also do the same on the other side because this is a square.So that means I will do 12.5+12.5 and I will get 25. Now for the number 7, I will do 7 x 2.5 and that will give me 17.5 but sense its a square I will do the same on the other side and I will get 35. So then I will add 25+35 and I will get 60.

The perimeter of the frame would be 60 ft.
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Hope this helps your brain.

~Jurgen

Answer 2

1)

PART-A Perimeter= 24 in.

PART-B Area of inside frame=6×4=24 square inches.

2)

• 2 in.×32 in.
• 4 in.×16 in.

4) Dimensions of outside frame= 12.5 ft×17.5 ft.

Explanation:

1)

PART-A

the outside frame has the measures as: 7 in. and 5 in.

i.e. the frame is in shape of a rectangle.

Perimeter of the outside edge= 7+7+5+5=14+10=24 in.

Hence, Perimeter= 24 in.

PART-B

Now we are asked to find the area of the inside of a frame as the frame is in the shape of a rectangle.

We know that the area of rectangle= l×b

where l represents the length of the frame and b represents the breadth of the rectangle.

Here we have l=6 in.

and b=4 in.

Hence, Area of inside frame=6×4=24 square inches.

2)

Now we are given that the area of the frame was 64 inches².

So the possible dimensions could be:

• 2 in.×32 in.
• 4 in.×16 in.

4)

Now we are using a scale factor as:

1 in.=2.5 ft.

the dimension of the outside frame was: 5 in.×7 in.

As 1 in.=2.5 ft.

5 in.=5×2.5=12.5 ft.

and 7 in.=7×2.5=17.5 ft.

Hence, the new dimension after using the scale factor is:

12.5 ft×17.5 ft.