Answer with Step-by-step explanation:
we are given a function:
![f(x)=(x^2-16)/(4x+24)](https://img.qammunity.org/2019/formulas/mathematics/high-school/1k5j3khqamimnmwazs460188ui52s9ie72.png)
We have to find the point of discontinuity of the function.
As we can clearly see that the function is not well defined if the denominator is zero.
So, the point of discontinuity is that value of x where denominator is zero
i.e. x such that 4x+24=0
4x= -24
x= -6
Hence, function is discontinuous at x= -6
and is continuous at all x ≠ -6