Question

What is the concentration of febr3 in a solution prepared by dissolving 10.0 g of febr3 in enough water to make 275 ml of solution?

Answer 1

10/ 56+ (80×3) =0.03
c=0.03/0.275 (i converted 275 ml into dm3)
=0.109

Answer 2

The correct answer is 0.1236 M.

Step-by-step explanation:

What is the concentration of
`FeBr_(3)` in a prepared solution by dissolving 10.0 g of
`FeBr_(3)` insufficient water to obtain 275 mL of solution?

First, we must look for the molar mass of iron bromide (III).

Mm = 295.56 g/mol

Then, the amount of
`FeBr_(3)` moles in 10 g is equal to:

n=
`(10g)/(295.56 (g)/(mol) )`

n= 0.034 mol

Now to know the molar concentration we have to divide the number of moles of the compound by the volume of the solution in liters:

Volume=
`275mL * (1L)/(1000mL)`

M=
`(0.034 mol)/(0.275 L)`

M=0.1236

Have a nice day!