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A spring is stretched from equilibrium to 0.90 m and the work done on the spring equals 18j what is the value of the spring constant
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A spring is stretched from equilibrium to 0.90 m and the work done on the spring equals 18j what is the value of the spring constant

User Phaze Phusion
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1 Answer

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work done is given by 1/2kx^2
18 = 1/2*k*0.9*0.9
36 = k*0.81
44.4 = j/m^2
User Nick Felker
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