Question

A woman throws a baseball from the back of an airplane to the front. From the perspective of the woman, the baseball travels at an average speed of 20 m/s. To an observer on the ground, the airplane is traveling at a constant speed of 820 km/h. What is the speed of the baseball from the perspective of the ground observer?

Answer 1

The speed of the baseball from the perspective of the ground observer is 247.78 m/s.

Step-by-step explanation:

To find the speed of the baseball from the perspective of the ground observer, we need to consider the velocity addition principle. According to this principle, if two velocities are added together, the resulting velocity is the sum of the individual velocities.

In this case, the airplane's speed is given as 820 km/h and the baseball's speed from the woman's perspective is given as 20 m/s. We need to convert the speed of the airplane to m/s to have consistent units.

820 km/h = (820 × 1000) m/ (3600) s = 227.78 m/s.

Now, using the velocity addition principle, we add the speed of the baseball with respect to the airplane (20 m/s) to the speed of the airplane with respect to the ground (227.78 m/s) to find the speed of the baseball with respect to the ground.

20 m/s + 227.78 m/s = 247.78 m/s.

Therefore, the speed of the baseball from the perspective of the ground observer is 247.78 m/s.

Answer 2

So for these questions, you add if they're going in the same direction and you subtract if it's in the opposite direction for the ground observer, since the ball is moving in the opposite direction of the plane, it would be 820 km/h - 15 m/s 15 m/s * 60 s/min * 60 min/hour = 54000 m/h, 54000 m/h * 1000 m/km = 54 km/h 820 km/h - 54 km/h = 768 km/h to the ground observer By the way, I don't think it's safe for someone to throw a baseball that fast in an airplan

25. It's travelling at constant speed so acceleration is 0
d = v * t
t = d / v
t = 732 000 / 327
t= 2238.5 secs = 37.31 minutes