Question

How many molecules are present in 936 g of glucose (C6H12O6)?

(The molar mass of glucose = 180.16 g/mol.)
A)3.14 × 1024 molecules
B)3.129 × 1024 molecules
C)3.1229 × 10-25 molecules
D)5.195 × 1023 molecules

Answer 1

Answer : The correct option is, (B)
`3.129* 10^(24)`

Explanation :

First we have to calculate the moles of glucose.

`\text{Moles of glucose}=\frac{\text{Mass of glucose}}{\text{Molar mass of glucose}}=(936g)/(180.16g/mole)=5.195mole`

Now we have to calculate the number of molecules present in glucose.

As we know that,

1 mole of a substance contains
`6.022* 10^(23)` number of molecules.

So, 5.195 mole of a substance contains
`5.195* (6.022* 10^(23))=31.286* 10^(23)=3.129* 10^(24)` number of molecules.

Therefore, the correct option is, (B)
`3.129* 10^(24)`