y = 4x + 4......so u have a slope of 4 and a y int of (0,4)
the x int can be found by subbing in 0 for y and solving for x
0 = 4x + 4
-4x = 4
x = -4/4
x = -1......and ur x int is (-1,0)
so go ahead and plot ur intercepts (0,4) and (-1,0)
start at (-1,0) and since u have a slope of 4......go up 4 spaces and to the right 1 space....plot that.....then up 4 and to the right 1....plot that...keep doing this and u will have crosses the y axis at (0,4).....connect ur plotted points and u have ur line.
Now if u want to find some points on ur line, just do some subbing....assign x a number and solve for y
y = 4x + 4......lets say x = 1
y = 4(1) + 4
y = 4 + 4
y = 8......so one point on ur line is (1,8)
y = 4x + 4.....lets say x = 2
y = 4(2) + 4
y = 8 + 4
y = 12....another point is (2,12)
u can keep doing this to find points or u can just graph it like I told u how above