Two similar parallelograms have areas of 18in^2 and 32in^2. find the ratio of their perimeters

asked Aug 21, 2019 19.7k views

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$\displaystyle\\ k = (P_1)/(P_2) = \sqrt{ (A_1)/(A_2) }=\sqrt{(18)/(32)}=\sqrt{(9*2)/(16*2)}=\sqrt{(9)/(16)}=(√(9))/(√(16))= \boxed{\bf (3)/(4)}$

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