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The length of a rectangle is twice the width. the perimeter is 90 inches. what is the rectangle's area? you write the equation 2w + 2w + w + w = 90 for the word problem. yo…

The length of a rectangle is twice the width. the perimeter is 90 inches. what is the rectangle's area? you write the equation 2w + 2w + w + w = 90 for the word problem. yo…
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The length of a rectangle is twice the width. the perimeter is 90 inches. what is the rectangle's area? you write the equation 2w + 2w + w + w = 90 for the word problem. you solve and get 15. what is the answer to the problem?

User Kimesha
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450 in. squared. after you get 15, substitute it for x in the length and width. this means you would have 2(15) X (15) whixh equals 450 in. squared
User Rehan Yousaf
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