Question

Solve x^2 + 4x + 8 = 0.

Answer 1

Explanation:

Answer 2

The solution to the quadratic equations are:

`x=-2+2i,\:x=-2-2i`

Explanation:

Consider the provided quadratic equation.

`x^2 + 4x + 8 = 0`

`\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_(1,\:2)=(-b\pm √(b^2-4ac))/(2a)`

Substitute a=1, b=4 and c=8 in above formula.

`x_(1,\:2)=(-4\pm √(4^2-4\cdot \:1\cdot \:8))/(2\cdot \:1)`

`x_(1,\:2)=(-4\pm √(16-32))/(2)`

`x_(1,\:2)=(-4\pm √(-16))/(2)`

`x_(1,\:2)=(-4\pm 4i)/(2)`

`x_(1,\:2)=-2\pm 2i`

Hence, the solution to the quadratic equations are:

`x=-2+2i,\:x=-2-2i`