m₁ = mass of car 1 = m
m₂ = mass of car 2 = 2 m
v₁ = speed of car 1 = v₂ = speed of car 2 = v
Kinetic energy of car 1 is given as
KE₁ = (0.5) m₁ v₁²
KE₁ = (0.5) m v² eq-1
Kinetic energy of car 2 is given as
KE₂ = (0.5) m₂ v₂²
KE₂ = (0.5) (2m) (v)²
KE₂ = 2 (0.5) m v²
Using eq-1
KE₂ = 2 KE₁
hence the correct choice is
Car 2 has twice the kinetic energy.