Question

On the position-time graph, what is the average velocity between 5 s and 10 s?

A.+2.0 m/s B. +4.0 m/s C.8.0 m/s D.3.0 m/s

Answer 1

To find the average velocity on a position-time graph between two time points, subtract the initial position from the final position to find displacement, then divide by the time interval. Using sample positions at 5 s and 10 s, the average velocity is calculated to be 2.0 m/s.

Step-by-step explanation:

To determine the average velocity between 5 s and 10 s from a position-time graph, you need to know the position of the object at these times. The average velocity is the displacement (the change in position) divided by the time interval over which the displacement occurs. In order to calculate this, the formula v = Δx / Δt is used, where Δx is the change in position and Δt is the change in time.

If the positions at 5 s and 10 s are given on the graph, for example, as 10 m and 20 m respectively, then the displacement is 20 m - 10 m = 10 m, and the time interval is 10 s - 5 s = 5 s. Therefore, the average velocity would be 10 m / 5 s = 2.0 m/s, which corresponds to answer option A.

Answer 2

For this case, we observe that in the interval of 5 to 10 seconds the behavior of the function is linear. Therefore, the average speed in that interval will be given by the slope of the line. This can be calculated as follows
m = (y2-y1) / (x2-x1)
Substituting the values of points A and C
m = ((30) - (10)) / ((10) - (5)) = 4
answer
the average velocity between 5 s and 10 s is 4m / s
B. +4.0 m / s