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Tabitha has a deck of cards numbered 1−10. She picks one card, puts it back in the deck and then chooses a second card. What is the probability that she picks an even number and then a 3?

2 Answers

6 votes
First compute the whole number of the possibilities :
10*9=90.
Compute the number of favorable possibilities:
There is 5 even numbers. Once we pick an even number,
we pick 5. So the number of the favorable possibilities is 5.
Now we compute the probability like this:

(5)/(90)
User Abhiieor
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4 votes

Tabitha has a deck of cards numbered 1, 2, 3, 4, 5, 6, 7, 8, 9, 10. There are 5 odd numbers 1, 3, 5, 7, 9 and 5 even numbers 2, 4, 6, 8, 10.

1. She picks one card from given 10 cards. The probability that she picks an even number is


Pr_1=(5)/(10)=(1)/(2).

2. She puts first card back in the deck and then chooses a second card. The probability that she picks card with number 3 is


Pr_2=(1)/(10).

3. Use the product rule to determine the probability that she picks an even number and then a 3:


Pr=Pr_1\cdot Pr_2=(1)/(2)\cdot (1)/(10)=(1)/(20)=0.05.

Answer: 0.05.

User Aaron Bratcher
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