23.8k views
4 votes
Mark and ann together were allocated n boxes of cookies to sell for a club project. mark sold 10 boxes less than n and ann sold 2 boxes less than n. if mark and ann have each sold at least one box of cookies, but together they have sold less than n boxes, what is the value of n ?

2 Answers

4 votes

Answer:


n=11

Step-by-step explanation:

Let m represent the number of boxes sold by mark and a represent the number of boxes sold by Ann.

We have been given that Mark sold 10 boxes less than n. We can represent this information in an equation as:


m=n-10...(1)

We are also told that Ann sold 2 boxes less than n. We can represent this information in an equation as:


a=n-2...(1)

Further, we are told that together they have sold less than n boxes. We can represent this information in an inequality as:


a+m<n...(3)

Now we will use substitution method to solve our system of equations.

Upon substituting equation (1) and (2) in (3) we will get,


n-2+n-10<n


2n-12<n


2n<n+12


2n-12+12<n+12


2n-n<n-n+12


n<12

The integer less than 12 is 11, therefore, the value of n is 11.

User Chayapol
by
8.0k points
3 votes
n = 11.

Step-by-step explanation:
Let m be the number of boxes Mark sells and a be the number of boxes Ann sells.

Since Mark sells 10 less than n, m = n-10. Since Ann sells 2 less than n, a = n-2.

Together, they sold n-10+n-2=2n-12 boxes.

We know that they sold less than n boxes, so our inequality would be
2n-12<n.

To solve this, subtract n from both sides:
2n-12-n<n-n; n-12<0.

Add 12 to both sides:
n-12+12<0+12; n<12.

This means there were less than 12 boxes. The next number down is 11; this woks because Mark sold 10 less than n; 11-10=1. Mark sold at least 1 box.

If n=10, however, 10-10=0; this doesn't work, because Mark did sell at least 1 box.
User MikeSli
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories