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A worker pushes a wheelbarrow with a force of 40 n over a level distance of 6.0 m. if a frictional force of 24 n acts on the wheelbarrow in a direction opposite to that of the worker, what net work is
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A worker pushes a wheelbarrow with a force of 40 n over a level distance of 6.0 m. if a frictional force of 24 n acts on the wheelbarrow in a direction opposite to that of the worker, what net work is done on the wheelbarrow?

User Gang Su
by
8.1k points

2 Answers

5 votes

Answer:

对不起，我不知道对不起

Step-by-step explanation:

User Ramez Ashraf
by
8.7k points
5 votes
Net work done = 40*6 - 24 *6
=96 j
User Jason Van Der Zeeuw
by
8.2k points
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