Answer:
The speed of the watte at a radius of 3 feet is 25 ft per sec.
Explanation:
Let s represents the speed of water and r represents the radius,
Since, the speed of water in a whirlpool varies inversely with the radius,
![\implies s\propto (1)/(r)](https://img.qammunity.org/2019/formulas/mathematics/college/nr019e2lv5t6phu77udlqsp24ajbc0j9qq.png)
![\implies s = (k)/(r)------(1)](https://img.qammunity.org/2019/formulas/mathematics/college/erkc13jm2xn8u6f9htscdhcy1qq3akyajr.png)
Where, k is the constant of proportionality,
Given,
When, s = 2.5 ft per sec then, r = 30 ft,
So, from equation (1),
![2.5 = (k)/(30)](https://img.qammunity.org/2019/formulas/mathematics/college/7b4qp1l996b9cfdazplsgqdiyulum9xna8.png)
![\implies k = 75](https://img.qammunity.org/2019/formulas/mathematics/college/m5pxobnz92iriq46eiohqtmbuc4wtur3s7.png)
Again from equation (1),
The equation that shows the relation between r and s is,
![s = (75)/(r)](https://img.qammunity.org/2019/formulas/mathematics/college/bxwpizu4kybrq2ilxwr3stmduxbjc5dfzh.png)
If r = 3 ft,
![s=(75)/(3)=25\text{ ft per sec}](https://img.qammunity.org/2019/formulas/mathematics/college/d0o1mza47mbudknogxqcoaecknnnywnvmz.png)