400,303 views
10 votes
10 votes
When a catapult is shot at angle of 35° and travels a horizontal distance 0.75 m and is in the air for 0.45 seconds. If the initial velocity is the same as the first trial (at 35"), how far would the catapult shoot the object if it was shot at an angle of 45°?​

User Zoonman
by
3.0k points

1 Answer

6 votes
6 votes

Final answer:

To find the distance the catapult would shoot the object if it was shot at an angle of 45°, we can use the horizontal distance and time of flight from the first trial as reference values. Using the formula: Horizontal distance = (initial velocity * time of flight) * cos(angle), we can set up a proportion to find the new distance.

Step-by-step explanation:

To find the distance the catapult would shoot the object if it was shot at an angle of 45°, we can use the horizontal distance and time of flight from the first trial as reference values.

Since the initial velocity is the same in both trials, and the horizontal distance is directly proportional to the time of flight, we can use a proportion to find the new distance.

Using the formula:

  • Horizontal distance = (initial velocity * time of flight) * cos(angle)

Starting with the values from the first trial:

  • Horizontal distance (1st trial) = 0.75 m
  • Time of flight (1st trial) = 0.45 s
  • Angle (1st trial) = 35°

Using the given values above and solving the proportion:

  • Horizontal distance (2nd trial) = (0.75 m * 0.45s * cos(35°)) / (0.45s * cos(45°))

Calculating this value gives us the answer for the distance the catapult would shoot the object if it was shot at an angle of 45°.

User Ramesh Kotha
by
2.7k points