Question

20% of a saline solution was mixed into saline solution with a concentration of 48% saline. How much of each solution be mixed together to obtain a solution of 8 milliliters with a 32% saline concentration

Answer 1

Below in bold.

Explanation:

Let x be the amount of 20% saline solution then the amount of 48% will

8 - x milliliters.

So,

0.20x + 0.48(8 - x) = 0.32* 8

0.20x + 3.84 - 0.48x = 2.56

-0.28x = -1.28

x = -1.28/-0.28

= 4.57 milliliters.

8 - x = 3.43 milliliters

The answer is:

4.57 milliliters of 20% solution and 3.43 milliliters of the 48% solution.