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Marcus plotted the points (0, 0), (6, 2), (18, 6) and (21, 7) on a graph. He wrote an equation for the relationship. Find another ordered pair that could be a solution of Marcus’s equitation. Justify your answer

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From the point (0, 0), we know that the y-intercept is 0.
If we use the slope formula on the first two points:

(2 - 0)/(6 - 0) = (2)/(6) = (1)/(3)
we get 1/3 as the slope.
Therefore, our equation in slope-intercept form is:

y = (1)/(3) x
To find a point, we can plug in any x and solve for y, let's use x=1

y = (1)/(3) * 12 = (12)/(3) = 4
Therefore, our point is (12, 4)
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