Question

In the Ridgeland Park youth athletics program, 60% of athletes play baseball and 24% of athletes play baseball and basketball.

What percentage of athletes who play baseball also play basketball?
would it be 40%?
because 24% of 60% is 40??
24/60 × 100/100 =
40/ 100

Answer 1

It is 0.4 for the awnser

Answer 2

The percentage of the athletes who play baseball also play basketball is 40 %.

Explanation:

Let A is the event that athlete plays baseball and B is the event that the athlete plays basketball,

According to the question,

The probability of being baseball player, P(A) = 60 % = 0.6

Also, the probability of being baseball player as well as basketball player, P(A∩B) = 24 % = 0.24,

Hence, the probability that athletes who play baseball also play basketball,

`P((B)/(A))=(P(A\cap B))/(P(A))=(0.24)/(0.6)=0.4=40\%`

Therefore, the percentage of the athletes who play baseball also play basketball is 40%.