Solve 2^x=32 and rewrite this equation in a logarithmic form. I have an answer for it, if someone wants to check it pls!

asked Nov 21, 2019 62.8k views

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Solve 2^x=32 and rewrite this equation in a logarithmic form.

I have an answer for it, if someone wants to check it pls!

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${2}^(x) = 32 \\ log( {2}^(x) ) = log(32) \\ xlog2 = log(32) \\ x = ( log(32) )/(2) \\ x = 5$

ByulTaeng answered Nov 24, 2019

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