Question

Solve 2^x=32 and rewrite this equation in a logarithmic form.

I have an answer for it, if someone wants to check it pls!

Answer 1

`{2}^(x) = 32 \\ log( {2}^(x) ) = log(32) \\ xlog2 = log(32) \\ x = ( log(32) )/(2) \\ x = 5`