Final answer:
The y-intercept of the quadratic equation y = x^2 + 3x - 10 is (0, -10). The x-intercepts are the roots of the equation obtained by solving for x when y = 0. The vertex of the equation is at (-1.5, -12.25), and the line of symmetry is the vertical line x = -1.5.
Step-by-step explanation:
To find various components of the quadratic equation y = x2 + 3x - 10, we analyze its structure:
- a. The y-intercept is the value of y when x equals 0. In this equation, if you set x to 0, y will be -10. Hence, the y-intercept is (0, -10).
- b. The x-intercepts are the points where the graph of the equation crosses the x-axis, which occur when y equals 0. To find them, we set the equation to 0 and solve for x: 0 = x2 + 3x - 10. Factoring the quadratic or using the quadratic formula would give us the x-intercepts.
- c. The vertex of a quadratic equation in the form y = ax2 + bx + c can be found by using the formula -b/(2a) for the x-coordinate, and then substituting this back into the equation for y. For our equation, the vertex is at x = -3/2 = -1.5, and y = (-1.5)2 + 3(-1.5) - 10 = -12.25, resulting in the vertex (-1.5, -12.25).
- d. The line of symmetry is a vertical line that passes through the vertex. Since the vertex has an x-coordinate of -1.5, the line of symmetry is x = -1.5.