For f(x) = 4x + 1 and g(x) = x2 – 5, find (f – g)(x). A. –x2 + 4x – 4 B. x2 – 4x – 6 C. –x2 + 4x + 6 D. 4x2

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For f(x) = 4x + 1 and g(x) = x2 – 5, find (f – g)(x). A. –x2 + 4x – 4 B. x2 – 4x – 6 C. –x2 + 4x + 6 D. 4x2 – 19

asked Mar 23, 2019 164k views

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For f(x) = 4x + 1 and g(x) = x2 – 5, find (f – g)(x). A. –x2 + 4x – 4 B. x2 – 4x – 6 C. –x2 + 4x + 6 D. 4x2 – 19

Mathematics
high-school

Jsarma asked

by Jsarma

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The answer is

$- {x}^(2) + 5$

$f = 4x + 1 \\ g = {x}^(2) - 5 \\ f - g = \\( 4x + 1) - ( {x}^(2) + 4x - 4) \\ 4x + 1 - {x}^(2) - 4x + 4 \\$

$- {x}^(2) + 4x - 4x + 1 + 4 \\ - {x}^(2) + 5$

Stsquad answered Mar 29, 2019

by Stsquad

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