Question

What is the solution to |2x+1|-3

Answer 1

to get rid of the -3 from the modulus your going to bring it over the equal sign

|2x+1|=3
To get rid of the modulus you square both sides.

`2x+1^(2) = {3}^(2) \\ {(2x + 1)}^(2) = {3}^(2)`


`(2x + 1 + 3) (2x + 1 - 3) = 0`

Postivite 3 solution is:


`2x + 1 + 3 = 0 \\ 2x + 4 = 0 \\ 2x = - 4 \\ x - 2`

Negative 3 solution is

`2x + 1 - 3 = 0 \\ 2x - 2 = 0 \\ 2x = 2 \\ x = 1`
Therefore x is -2 and 1