143k views
5 votes
What is the point-slope form of a line that has a slope of 5 and passes through the point (3, –4)?

y – 3 = 5[x – (–4)]
–4 – y1 = 5(3 – x1)
y – (–4) = 3(x – 5)
y – (–4) = 5(x – 3)

User Oruchreis
by
8.3k points

2 Answers

4 votes

Answer:

y – (–4) = 5(x – 3)

Explanation:

User Woko
by
7.6k points
3 votes
The generic form for this case is given by
y = m (x-xo) + yo
where
xo: x coordinate
me: y coordinate
Substituting the values we have
y = 5 (x-3) - 4
Therefore, the answer in this case is
y – (–4) = 5(x – 3)
User AnimatedRNG
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories