Question

Find a Point-Slope equation for a line containing the given point and having the given slope. (4, -3); m = -1​

Answer 1

`y+3=-(x-4)`

Explanation:

Pre-Solving

We are given that a line has a slope (m) of -1 and passes through the point (4, -3).

We want to write the equation of this line in point-slope form.

Point-slope form is given as
`y-y_1=m(x-x_1)` where m is the slope and
`(x_1,y_1)` is a point.

Solving

Since we already know the values of the point and slope, we can plug those values into the formula.

Starting with the slope, substitute -1 as m.

`y-y_1=-1(x-x_1)`

When -1 is a coefficient, we can rewrite things to become:

`y-y_1=-(x-x_1)`

Now, substitute 4 as
`x_1` and -3 as
`y_1`.

`y--3=-(x-4)`

This can be simplified to:

`y+3=-(x-4)`

Answer 2

9514 1404 393

Answer:

y +3 = -(x -4)

Explanation:

The point-slope form of the equation for a line is ...

y -k = m(x -h) . . . . . . line with slope m through point (h, k)

Fill in the given values.

y -(-3) = -1(x -4)

y +3 = -(x -4)