83.9k views
3 votes
Suppose you are asked to pick 3 numbers from 1 to 20 to win a prize. What is the probability that one of the numbers you will pick is the winning number?

2 Answers

1 vote
Another way to calculate it is:

P(1st pick is not the winner) = 19/20 because 1 out of 20 is winner
P(2nd pick is not the winner) = 18/19 because only 19 numbers left
P(3rd pick is not the winner) = 17/18

P(not picking the winner) = P(1 no win) * P(2 no win) * P(3 no win)
=19/20 * 18/19 * 17/18 = 17/20

P(picking winner) = 1 - P(no win) = 1 -17/20
= 3/20 = 0.15


User Verdure
by
6.5k points
6 votes
Each number has a 1/20 chance of being the winner.
You pick 3 numbers, so you have three times the chance of having the winning number.

3 * 1/20 = 3/20 = 0.15

The probability you have the winning number is 0.15.
User Davidvera
by
6.9k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.