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Suppose you are asked to pick 3 numbers from 1 to 20 to win a prize. What is the probability that one of the numbers you will pick is the winning number?
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Jan 28, 2019
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Suppose you are asked to pick 3 numbers from 1 to 20 to win a prize. What is the probability that one of the numbers you will pick is the winning number?
Mathematics
high-school
Thong Yi Xuen
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Thong Yi Xuen
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Another way to calculate it is:
P(1st pick is not the winner) = 19/20 because 1 out of 20 is winner
P(2nd pick is not the winner) = 18/19 because only 19 numbers left
P(3rd pick is not the winner) = 17/18
P(not picking the winner) = P(1 no win) * P(2 no win) * P(3 no win)
=19/20 * 18/19 * 17/18 = 17/20
P(picking winner) = 1 - P(no win) = 1 -17/20
= 3/20 = 0.15
Verdure
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Jan 28, 2019
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Each number has a 1/20 chance of being the winner.
You pick 3 numbers, so you have three times the chance of having the winning number.
3 * 1/20 = 3/20 = 0.15
The probability you have the winning number is 0.15.
Davidvera
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Feb 2, 2019
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Davidvera
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