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What is the volume occupied by 3.00 × 1023 molecules of bromine gas at STP? a 404.5 L B. 0.80 L C. 2.2 × 10-2 D. 11.2 L
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Oct 27, 2019
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What is the volume occupied by 3.00 × 1023 molecules of bromine gas at STP?
a 404.5 L
B. 0.80 L
C. 2.2 × 10-2
D. 11.2 L
Chemistry
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Sergey Podobry
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Answer:
The answer is 11.2 L.
Step-by-step explanation:
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Gijs Brandsma
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Oct 30, 2019
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D. 11.2 L , since we are at STP we will use the ideal gas law. 3.0 x 10²³ 6.02x10²³ / 1 mole and if you continue with this process it will give you 11 L.
Ellin
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Nov 2, 2019
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Ellin
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